What is the polar form of #( 25,16 )#?
1 Answer
Feb 15, 2016
#(sqrt881 , 0.57 )#
Explanation:
using the formulae that links Cartesian to Polar coordinates.
#• r^2 = x^2 + y^2 #
#• theta = tan^-1(y/x) # here x = 25 and y = 16
hence
#r^2 = 25^2 + 16^2 = 881 rArr r = sqrt881# and
#theta = tan^-1(16/25) = 0.57 "radians"#
