# What is the polar form of ( 25,16 )?

Feb 15, 2016

$\left(\sqrt{881} , 0.57\right)$

#### Explanation:

using the formulae that links Cartesian to Polar coordinates.

• r^2 = x^2 + y^2

• theta = tan^-1(y/x)

here x = 25 and y = 16

hence ${r}^{2} = {25}^{2} + {16}^{2} = 881 \Rightarrow r = \sqrt{881}$

and $\theta = {\tan}^{-} 1 \left(\frac{16}{25}\right) = 0.57 \text{radians}$