What is the polar form of #( -27,15 )#?
1 Answer
Jan 23, 2016
# ( sqrt954 , 2.63 )#
Explanation:
Use the following formulae that links Cartesian to Polar coordinates.
# • r^2 = x^2 + y^2 #
#• theta = tan^-1 (y/x) # Here x = - 27 and y = 15 .[ Note also that (-27 , 15 ) is a point in
the 2nd quadrant and so care must be taken to ensure
#theta # is in the 2nd quadrant.]
# r^2 = (-27)^2 + (15)^2 = 729 + 225 = 954 #
# rArr r = sqrt954 #
# theta = tan^-1 (15/-27) =- 0.51 color(black)("radians") # To find
#theta color(black)(" in the 2nd quadrant") #
#theta = ( pi - 0.51 ) =2.63 color(black)(" radians") #
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