What is the polar form of #( -27,15 )#?

1 Answer
Jan 23, 2016

# ( sqrt954 , 2.63 )#

Explanation:

Use the following formulae that links Cartesian to Polar coordinates.

# • r^2 = x^2 + y^2 #

#• theta = tan^-1 (y/x) #

Here x = - 27 and y = 15 .[ Note also that (-27 , 15 ) is a point in

the 2nd quadrant and so care must be taken to ensure #theta #

is in the 2nd quadrant.]

# r^2 = (-27)^2 + (15)^2 = 729 + 225 = 954 #

# rArr r = sqrt954 #

# theta = tan^-1 (15/-27) =- 0.51 color(black)("radians") #

To find #theta color(black)(" in the 2nd quadrant") #

#theta = ( pi - 0.51 ) =2.63 color(black)(" radians") #

.