What is the polar form of #( 8,3 )#?
1 Answer
Jan 14, 2016
#(sqrt73 , 0.36 ) #
Explanation:
Making use of the formulae that links Cartesian to Polar coordinates.
# r^2 = x^2 + y^2 and theta = tan^-1(y/x ) # For (8 , 3 ) :
# r^2= 8^2 + 3^2 = 64 + 9 = 73 rArr r = sqrt73 # and
#theta = tan^-1(3/8 ) ≈ 0.36 radians #