What is the polar form of ( 9,12 )?

Feb 3, 2017

$\left(15 , {53.13}^{0}\right)$

Explanation:

polar form is $\left(r , \theta\right)$

$r = \sqrt{{x}^{2} + {y}^{2}} = \sqrt{{9}^{2} + {12}^{2}}$

$= \sqrt{81 + 144} = \sqrt{225} = 15$

$\tan \theta = \frac{y}{x} = \frac{12}{9}$
$\theta = {\tan}^{-} 1 \left(\frac{12}{9}\right)$

$\theta = {53.13}^{0}$

the point of $\left(9 , 12\right)$ is $\left(15 , {53.13}^{0}\right)$ in polar form.