What is the pressure in a 10.6-L cylinder filled with 11.2 g of oxygen gas at a temperature of 345 K?

1 Answer
May 6, 2016

Answer:

Approx. #"1 atm"#

Explanation:

We use the Ideal gas equation with appropriate units. #R =0.0821*L*atm*K^-1*mol^-1#, is probably most useful for chemists.

#P=(nRT)/V# #=# #((11.2*cancelg)/(32.0*cancelg*cancel(mol^-1))*0.0821*cancelL*atm*cancel(K^-1)*cancel(mol^-1)xx345*cancel(K))/(10.6*cancelL)# #~=# #1*atm#

The most difficult part of this question is choosing the most appropriate gas constant, #R#. For chemists, #R=0.0821*L*atm*K^-1*mol^-1# is probably most useful, because it uses the units that with which chemists typically deal. In an examination, several values of the gas constant should be quoted as supplementary material.