Question

What is the pressure in a 19.3-L cylinder filled with 16.7 g of oxygen gas at a temperature of 319 K?

Answer 1

`P=(nRT)/V~=0.70*atm`

Explanation:

`((16.00*g)/(32.00*g*mol^-1)xx0.0821(L*atm)/(K*mol)xx319*K)/(19.3*L)~=0.70*atm`

Why did I have to divide the mass of the oxygen gas by `32`?