# What is the pressure inside a tank that has a volume of 1.20 * 10^3 L and contains 12.0 kg of HCl gas at a temperature of 18°C?

Approx. $0.7 \cdot a t m$
If we assume ideality, $P = \frac{n R T}{V}$
$=$ $\frac{12 \times {10}^{3} \cdot g \times 0.0821 \cdot L \cdot a t m \cdot {K}^{-} 1 \cdot m o {l}^{-} 1 \times 301 \cdot K}{38.0 \cdot g \cdot m o {l}^{-} 1 \times 12 \times {10}^{3} \cdot L}$
$=$ ??atm