What is the product of #3+2i# and #1+7i#? Precalculus Complex Numbers in Trigonometric Form Multiplication of Complex Numbers 1 Answer Manish Bhardwaj · AJ Speller Sep 28, 2014 #( 3 +2i ) (1 + 7i)# #3 (1 +7i) +2i ( 1+ 7i)# Using distributive property ; #3 x 1 + 3 * 7i + 2i * 1 + 2i * 7i# #3 + 21 i +2 i + 14 i^2# # i^2 = -1# #3 + 23 i + 14 (-1)# #3 + 23i -14# #23 i -11# or #-11 + 23i# Answer link Related questions How do I multiply complex numbers? How do I multiply complex numbers in polar form? What is the formula for multiplying complex numbers in trigonometric form? How do I use the modulus and argument to square #(1+i)#? What is the geometric interpretation of multiplying two complex numbers? How do I use DeMoivre's theorem to solve #z^3-1=0#? How do I find the product of two imaginary numbers? How do you simplify #(2+4i)(2-4i)#? How do you multiply #(-2-8i)(6+7i)#? How do you multiply #(3+2i)(1-3i)#? See all questions in Multiplication of Complex Numbers Impact of this question 9080 views around the world You can reuse this answer Creative Commons License