# How do you multiply (-2-8i)(6+7i)?

Feb 10, 2015

You multiplly as in a normal multiplication remembering that $i = \sqrt{- 1}$ and so ${i}^{2} = - 1$;

so you get:

$\left(- 2 - 8 i\right) \left(6 + 7 i\right) =$
$= - 12 - 14 i - 48 i - 56 {i}^{2} =$
$= - 12 - 62 i - \left(- 1 \cdot 56\right) = 44 - 62 i$