# What is the product of the oxidation of a ketone?

Jan 14, 2016

Naturally, oxidation in the context of organic chemistry can be thought as, wouldn't you know it, adding oxygen (or removing hydrogen).

For a ketone, we have a problem. It can't be oxidized any further via the removal of a hydrogen. There is no product when trying to oxidize a ketone in that manner.

What happens when you reduce a ketone? You get to a secondary alcohol.

Let's start from the secondary alcohol and see the mechanism to get to a ketone by using the Swern oxidation (Organic Chemistry, Bruice, Ch. 20.4). Afterwards, we should see how repeating that mechanism for a ketone fails.

1. The alcohol backside-attacks a dimethylchlorosulfonium ion (formed by adding dimethyl sulfoxide and oxalyl chloride together), and the chloride leaves. This forms a $+ 2$-charged intermediate.
2. At this point, some suitable base deprotonates the unstable intermediate, such as another equivalent of the alcohol.

3. Then here's the important step: The triethylamine added acts as a proton acceptor to perform a second-order elimination ($E 2$) reaction, which requires a proton attached to what becomes the carbonyl carbon.

That was a secondary alcohol getting oxidized.

But a ketone doesn't have any protons attached to the carbonyl carbon, so this step is impossible to perform. And in fact, this step would typically be the key to oxidizing a ketone, so it's just not going to work.

Granted, a Baeyer-Villiger oxidation would work to form an ester, but that's an unusual reaction...