What is the quadratic formula for #2x^2 - 3x - 5 = 0#?

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Answer 1 · 2018-08-04T16:11:26

#x = 5/2# and #-1#

#2x^2 - 3x - 5 = 0#

The quadratic formula is #x = (-b +- sqrt(b^2 - 4ac))/(2a)#.

This equation is in standard quadratic form, so we know that:
#a = 2#, #b = -3#, and #c = -5#.

Plug them into the equation and solve for #x#:
#x = (-(-3) +- sqrt((-3)^2 - 4(2)(-5)))/(2(2))#

#x = (3 +- sqrt(9 + 40))/4#

#x = (3 +- sqrt(49))/4#

#x = (3 +- 7)/4#

#x = 10/4# and #-4/4#

#x = 5/2# and #-1#

Hope this helps!