# What is the range of the function #f(x)=(3x^2+3x-6)/(x^2-x-12)#?

##### 2 Answers

#### Answer:

The range is

#### Explanation:

Let

To find the range, proceed as follows

This is a quadratic equation in

Therefore,

The range is

graph{(3x^2+3x-6)/(x^2-x-12) [-14.24, 14.23, -7.12, 7.12]}

#### Answer:

**Range:**

#### Explanation:

Therefore range is any real value ,i.e

Range:

graph{(3x^2+3x-6)/(x^2-x-12) [-40, 40, -20, 20]} [Ans]