Question

What is the reference angle when theta is -1.8? and Why?

Answer 1

The reference angle is always `0^o` by default.

Explanation:

If not otherwise specified, the standard reference for angles is always `0^o` (E or x-axis) `rArr 90^o` is N, `180^o W, 270^o S`.

If theta is expressed as -`1.8^o` without giving any other reference, then it is `1.8^o`clockwise from the East (or x-axis) by default.

BTW, is theta -`1.8^o` or -1.8 radians?