# What is the remainder when (-2x^4 - 6x^2 + 3x + 1) div ( x + 1)?

Dec 31, 2015

$- 10$

#### Explanation:

From the remainder theorem theory, we may simply find the required remainder by evaluating $f \left(- 1\right)$ in (f(x)=-2x^4-6x^2+3x+1.

Doing so yields

$f \left(- 1\right) = - 2 {\left(- 1\right)}^{4} - 6 {\left(- 1\right)}^{2} + 3 \left(- 1\right) + 1$

$= - 2 - 6 - 3 + 1$

$= - 10$.