What is the remainder when #p(x) = x ^99 +2x^89+ 3x^79+4x^69+ 5x^59 +6x^49+7x^39 +8x^29+9x^19 +10x^9+11 #is divided by#x-1#?

1 Answer
Oct 24, 2017

There is a remainder of #66#.

Explanation:

Use the remainder theorem, which states that if #x - a# is a factor of #p(x)#, then #p(a) # gives the remainder.

#p(1) = 1+ 2 + 3 + 4 + 5+ 6 + 7 + 8 + 9+ 10 + 11 = 66#

So the remainder is of #66#.

Hopefully this helps!