# What is the result if you divide -12x^8y^8 by 3x^4y^2?

$- 4 {x}^{4} {y}^{6}$
Given: $\frac{- 12 {x}^{8} {y}^{8}}{3 {x}^{4} {y}^{2}}$
Use the exponent rule: ${x}^{m} / {x}^{n} = {x}^{m - n}$
$\frac{- 12 {x}^{8} {y}^{8}}{3 {x}^{4} {y}^{2}} = - \frac{12}{3} {x}^{8 - 4} {y}^{8 - 2} = - 4 {x}^{4} {y}^{6}$