# What is the second derivative of f(x) = e^(-x^2 -3x) ?

$\left({e}^{- {x}^{2} - 3 x}\right) \left(4 {x}^{2} + 12 x + 7\right)$
$f ' \left(x\right) = \left(- 2 x - 3\right) {e}^{- {x}^{2} - 3 x}$.
$f ' ' \left(x\right) = {\left(- 2 x - 3\right)}^{2} \cdot {e}^{- {x}^{2} - 3 x} - 2 \left({e}^{- {x}^{2} - 3 x}\right)$
$= \left({e}^{- {x}^{2} - 3 x}\right) \left(4 {x}^{2} + 12 x + 7\right)$.