# What is the slope any line perpendicular to the line passing through (-3,1) and (5,12)?

##### 1 Answer
Aug 28, 2017

Slope of the perpendicular line is $- \frac{8}{11}$

#### Explanation:

Slope of the line passing through $\left(- 3 , 1\right) \mathmr{and} \left(5 , 12\right)$ is

$m = \frac{{y}_{2} - {y}_{1}}{{x}_{2} - {x}_{1}} = \frac{12 - 1}{5 + 3} = \frac{11}{8}$

The product of slope of perpendicular lines is $= - 1$

$\therefore m \cdot {m}_{1} = - 1 \mathmr{and} {m}_{1} = - \frac{1}{m} = - \frac{1}{\frac{11}{8}} = - \frac{8}{11}$

Slope of the perpendicular line is $- \frac{8}{11}$ [Ans]