# What is the slope of 7/3y=4/3y-x/4+1?

Apr 7, 2018

The slope is $- \frac{1}{4}$.

Here's how I did it:

#### Explanation:

$\frac{7}{3} y = \frac{4}{3} y - \frac{x}{4} + 1$

First, let's subtract $\frac{4}{3} y$ from both sides of the equation:
$\frac{3}{3} y = - \frac{x}{4} + 1$

$y = - \frac{x}{4} + 1$

Now this equation is written in:

As you can see, the slope is the value in front of the $x$. In our case, that value is $- \frac{1}{4}$. Therefore, the slope is $- \frac{1}{4}$.

Hope this helps!