What is the slope of #7/3y=4/3y-x/4+1#?

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Answer 1 · 2018-04-07T00:12:36

The slope is #-1/4#.

Here's how I did it:

#7/3y = 4/3y - x/4 + 1#

First, let's subtract #4/3y# from both sides of the equation:
#3/3y = -x/4 + 1#

#y = -x/4 + 1#

Now this equation is written in:
www.katesmathlessons.com

As you can see, the slope is the value in front of the #x#. In our case, that value is #-1/4#. Therefore, the slope is #-1/4#.

Hope this helps!