What is the slope of a line perpendicular to Ax+By+C=0?

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Answer 1 · 2016-07-31T05:16:31

#Bx-Ay+C=0#

Given -

#Ax+By+C=0#

In such case you have to interchange the co-efficients of #x# and #y# and then change the sign of the coefficient of #y#

The equation of the perpendicular line is

#Bx-Ay+C=0#

You can check it by using the formula

#m_1xxm_2=-1#

Slope of the first line -

#m_1=-a/b=-A/B#

Slope of the second line -

#m_2=-a/b=-B/(-A)=B/A#

Substituting these values in the formula #m_1xxm_2=-1#

We get -

#-cancelA/cancelB xx cancelB/cancelA=-1#