Question

What is the slope of a line perpendicular to the line whose equation is `20x-2y=6`?

Answer 1

The perpendicular slope would be `m=1/10`

Explanation:

We begin finding the slope converting the equation to the form `y=mx+b`

`20x-2y=6`

`cancel(20x)cancel(-20x) -2y = -20x +6`

`(cancel(-2)y)/cancel(-2)= (-20x)/-2 + 6`

`y = -10x + 6`

The slope of this equation of the line is `m=-10`

The line perpendicular to this line would have an inverse slope with is the reciprocal of the slope with the sign changed.

The reciprocal of `m=-10` is `m = 1/10`