What is the slope of a line that is perpendicular to #-2x -3y =0#?

1 Answer
Nov 24, 2017

#3/2#

Explanation:

We first solve for #y# so that we rewrite the equation of this line in #y=mx+b# form where #m# is the slope and #b# is the #y#- intercept

So #-2x-3y=0# becomes

#-3y=2x#

#y=-2/3x#

In this equation #-2/3x# is our #m# or slope so to find the slope perpendicular to the line we must apply the following:

Perpendicular Slope #=-1/m=-1/(-2/3)=3/2#

So the slope perpendicular to #y=-2/3x# is #3/2#