What is the slope of a line that is perpendicular to $-2x -3y =0$ ?

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Answer 1 · 2017-11-24T04:51:22

$3/2$

We first solve for $y$ so that we rewrite the equation of this line in $y=mx+b$ form where $m$ is the slope and $b$ is the $y$ - intercept

So $-2x-3y=0$ becomes

$-3y=2x$

$y=-2/3x$

In this equation $-2/3x$ is our $m$ or slope so to find the slope perpendicular to the line we must apply the following:

Perpendicular Slope $=-1/m=-1/(-2/3)=3/2$

So the slope perpendicular to $y=-2/3x$ is $3/2$

What is the slope of a line that is perpendicular to -2x -3y =0-2x -3y =0?