What is the slope of a line that passes through (-2, -3) and (1, 1)?

2 Answers
Jun 16, 2018

See a solution process below:

Explanation:

The formula for find the slope of a line is:

#m = (color(red)(y_2) - color(blue)(y_1))/(color(red)(x_2) - color(blue)(x_1))#

Where #(color(blue)(x_1), color(blue)(y_1))# and #(color(red)(x_2), color(red)(y_2))# are two points on the line.

Substituting the values from the points in the problem gives:

#m = (color(red)(1) - color(blue)(-3))/(color(red)(1) - color(blue)(-2)) = (color(red)(1) + color(blue)(3))/(color(red)(1) + color(blue)(2)) = 4/3#

Jun 16, 2018

Slope: #4/3#

Explanation:

The slope of a line between two points #color(blue)(""(x_1,y_1))# and #color(green)(""(x_2,y_2))#
is the difference between the #y# coordinate values divided by the difference between the #x# coordinate values (taken in the same order);
that is
#color(white)("XXX")"slope" = (color(green)(y_2)-color(blue)(y_1))/(color(green)(x_2)-color(blue)(x_1))#

In this case we have the points #color(blue)(""(-2,-3))# and #color(green)(""(1,1))# (notice that the order of listing these does not matter)
So
#color(white)("XXX")"slope"=(color(green)1-color(blue)(""(-3)))/(color(green)1-color(blue)(""(-2)))=4/3#