# What is the slope of any line perpendicular to the line passing through (-2,5) and (-8,1)?

Feb 3, 2016

First, find the slope of the line between these points.

#### Explanation:

The formula for slope m = $\frac{{y}_{2} - {y}_{1}}{{x}_{2} - {x}_{1}}$

m = $\frac{{y}_{2} - {y}_{1}}{{x}_{2} - {x}_{1}}$

m = $\frac{1 - 5}{- 8 - \left(- 2\right)}$

m = $- \frac{4}{6}$

m = $- \frac{2}{3}$

The slope of a line perpendicular to this one has a slope that is the negative reciprocal of m.

So, the new slope is $\frac{3}{2}$

Practice exercises:

1. Here is the graph of a linear function. Find the slope of the line perpendicular to this one.

graph{y = 1/2x + 1 [-10, 10, -5, 5]}eh equations of the lines perpendicular

1. Below are linear function equations or linear function characteristics. Find the equations of the lines perpendicular to these functions:

a) 2x + 5y = -3

b) y - 2 = $\frac{1}{3}$(2x - 6)

c) Has an x intercept at (2,0) and a y intercept at (-5,0).

Good luck!