Question

What is the slope of any line perpendicular to the line passing through `(-9,8)` and `(0,0)`?

Answer 1

First, find the slope of the original line.

Explanation:

m = `(y_2 - y_1)/(x_2 - x_1)`

m = `(0 - 8)/ (0 -(-9))`

m = `-8/9`

The slope of a line perpendicular to that line would be the negative reciprocal. To find this, invert the numerator and the denominator and multiply by -1, which gives you m = `9/8`

So, the slope of any line perpendicular to the line passing through (-9, 8) and (0,0) is `9/8`.