What is the slope of the line normal to the tangent line of #f(x) = xe^-x+x^2-x # at # x= 0 #?
1 Answer
Apr 27, 2018
Normal is vertical and hence its slope is not defined.
Explanation:
Slope of a tangent to the curve
Here
=
and at
i.e. at
and hence normal, which is always perpendicular to tangent
and hence its slope is not defined.
graph{xe^(-x)+x^2-x [-2.5, 2.5, -1.25, 1.25]}