# What is the slope of the line normal to the tangent line of #f(x) = xe^-x+x^2-x # at # x= 0 #?

##### 1 Answer

Apr 27, 2018

Normal is vertical and hence its slope is not defined.

#### Explanation:

Slope of a tangent to the curve

Here

=

and at

i.e. at

and hence normal, which is always perpendicular to tangent

and hence its slope is not defined.

graph{xe^(-x)+x^2-x [-2.5, 2.5, -1.25, 1.25]}