What is the slope of the line passing through (1,-1); (-4,-8)?

Mar 13, 2018

A slope's gradient ($m$) is equal to its rise (change in y value), over run (change in x value) or $\frac{{y}_{2} - {y}_{1}}{{x}_{2} - {x}_{1}}$.
Let $\left({x}_{1} , {y}_{1}\right) = \left(1 , - 4\right)$ and $\left({x}_{2} , {y}_{2}\right) = \left(- 4 , - 8\right)$.
Substituting our values into this formula and solving, we get:
$m = \frac{- 8 + 4}{- 4 - 1}$
$m = \frac{- 4}{-} 5$
$m = \frac{4}{5}$
Therefore the gradient of the slope is $\frac{4}{5}$ or $0.8$.

Mar 13, 2018

The slope of the line is $\frac{7}{5}$

Explanation:

The slope of the line passing through $\left(1 , - 1\right) \mathmr{and} \left(- 4 , - 8\right)$ is

$m = \frac{{y}_{2} - {y}_{1}}{{x}_{2} - {x}_{1}} = \frac{- 8 + 1}{- 4 - 1} = \frac{- 7}{-} 5 = \frac{7}{5}$

The slope of the line is $\frac{7}{5}$ [Ans]