What is the slope of the line passing through #(1,-1); (-4,-8)#?

2 Answers
Mar 13, 2018

A slope's gradient (#m#) is equal to its rise (change in y value), over run (change in x value) or #(y_2 - y_1)/(x_2 - x_1)#.
Let #(x_1,y_1) = (1,-4)# and #(x_2,y_2) = (-4, -8)#.
Substituting our values into this formula and solving, we get:
#m = (-8+4)/(-4-1)#
#m = (-4)/-5#
#m = 4/5#
Therefore the gradient of the slope is #4/5# or #0.8#.

Mar 13, 2018

The slope of the line is #7/5#

Explanation:

The slope of the line passing through #(1,-1) and (-4,-8)# is

#m= (y_2-y_1)/(x_2-x_1)= (-8+1)/(-4-1)= (-7)/-5=7/5#

The slope of the line is #7/5# [Ans]