What is the slope of the line perpendicular to # y=-1/4x-5 #?

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Answer 1 · 2018-03-11T04:19:23

#m'=4#

Intercept form of the equation

#=> y=mx+c#

Here , #m# is the slope of the line.

The given equation is

#=> y=-1/4 x -5#

On equating , you get #m=-1/4#.

So , slope of the given line is #-1/4#.

Product of slope of two perpendicular lines = -1.

#=>#Slope of given line #(m) xx# slope of perpendicular line #(m') = -1#

#=>m xx m' = -1#

We found #m=-1/4#

Put this value in the equation.

#=> -1/4 xx m' =-1#

#=>(m')/4=1#

#=> m'=4#

So , slope of the line perpendicular to the given line is equal to 4.