# What is the slope of the line perpendicular to  y=-3/4x+11 ?

Apr 10, 2018

$\frac{4}{3}$

#### Explanation:

First, identify your slope. The function you presented follows $y = m x + b$ wherein $m$ is the slope, which is $- \frac{3}{4}$.

The slope of the line perpendicular to a given slope is the negative reciprocal of it.

That is, if we have a slope ${m}_{1}$, and a slope perpendicular to it, ${m}_{2}$, then, ${m}_{1} \cdot {m}_{2} = - 1$

In your case, $\frac{4}{3} \cdot - \frac{3}{4} = - 1$, thus the answer $\frac{4}{3}$.