# What is the slope of the line perpendicular to  y=-7/3x-4 ?

$\frac{3}{7}$
As the equation is already in the slope intercept form $y = m x + c$, the slope of line $y = - \frac{7}{3} x - 4$ is $- \frac{7}{3}$. As product of slopes of two perpendicular lines is $- 1$, hence slope of line perpendicular to it is $- \frac{1}{- \frac{7}{3}}$ or $\frac{3}{7}$.