Question

What is the slope of the line that contains the points (-6, -2) and (3, -2)?

Answer 1

slope = 0

Explanation:

To find the slope use the `color(blue)"gradient formula"`

`color(red)(bar(ul(|color(white)(2/2)color(black)(m=(y_2-y_1)/(x_2-x_1))color(white)(2/2)|)))`
where m represents the slope and `(x_1,y_1),(x_2,y_2)" are 2 points on the line"`

The 2 points here are (-6 ,-2) and (3 ,-2)

let `(x_1,y_1)=(-6,-2)" and " (x_2,y_2)=(3,-2)`

`rArrm=(-2-(-2))/(3-(-6))=0/9=0`

However, if we consider the 2 points (-6 ,-2) and (3 ,-2) we note that the y-coordinates have the same value. That is y = -2

This indicates that the line is horizontal and parallel to the x-axis.

Since the x-axis has a slope = 0, then the slope of a parallel line to it will also have a slope = 0.