# What is the slope of the tangent line of #secx-cscy= C #, where C is an arbitrary constant, at #(pi/3,pi/3)#?

##### 1 Answer

Jul 31, 2018

#### Explanation:

As a point of the curve is

y' at T

Graph, with tangent:

graph{(1/cos x- 1/ sin y - 2 ( 1- 1/3 sqrt3 ))(y-1/3pi+3sqrt3(x-1/3pi))(y-1/3pi-3sqrt3(x+1/3pi))((x-1/3pi)^2+(y-1/3pi)^2-0.025)((x+1/3pi)^2+(y-1/3pi)^2-0.025)=0}

Indeed, vivid.

Did you observe that I have shown also

the tangent at