# What is the slope of the tangent line of #(x-y)^3-y^2-yx= C #, where C is an arbitrary constant, at #(1,-1)#?

##### 1 Answer

Nov 4, 2016

slope =

#### Explanation:

To find the slope of the tangent line we have to find the derivative of the function first.

Now plug in 1 for x and -1 for y