# What is the smallest of the three numbers if the sum of three consecutive numbers is 72?

Sep 28, 2014

Let us assume the smallest number is x , and if x is the smallest number. the other two numberers x+1 , and x+2 .

The sum of these three numbers is $72$

$x + \left(x + 1\right) + \left(x + 2\right) = 72$

$x + x + 1 + x + 2 = 72$

$3 x + 3 = 72$

solving for $x$

subtract $3$ from both sides;

$3 x + 3 - 3 = 72 - 3$

$3 x = 69$

Divide both the sides by $3$

$\frac{3 x}{3} = \frac{69}{3}$

$x = 23$