# What is the smallest possible value of the principal quantum number n for an s electron?

Mar 28, 2018

$n = 1$

#### Explanation:

Well, an electron in the $s$ orbital would mean that the orbital angular momentum quantum number $l$ is $0$.

We know that the principal quantum number $n$ and $l$ is related by:

$l = 0 , 1 , 2 , 3 , \ldots \left(n - 1\right)$

And so, ${n}_{\min} = l + 1$

$= 0 + 1$

$= 1$