What is the solubility of silver nitrate if only 11.1 g can dissolve in 5.0 g water at 20°C?

1 Answer
May 27, 2016

Answer:

#"220 g/100 g H"_2"O"#

Explanation:

A compound's solubility in water is usually expressed in grams per #"100 g"# of water, or, alternatively, in grams per #"100 mL"# of water.

In your case, you can use the information given to you to find the solubility of silver nitrate, #"AgNO"_3#, in water at #20^@"C"#, in grams per #"100 g"# of water, #"g/100 g H"_2"O"#.

So, you know that you can dissolve #"11.1 g"# of silver nitrate in #"5.0 g"# of water at #20^@"C"#. You can use this as a conversion factor to determine how much silver nitrate can be dissolved in #"100 g"# of water at the same temperature

#100color(red)(cancel(color(black)("g H"_2"O"))) * "11.1 g AgNO"_3/(5.0color(red)(cancel(color(black)("g H"_2"O")))) = "222 g"#

This means that the solubility of the salt will be

#"solubility AgNO"_3 = color(green)(|bar(ul(color(white)(a/a)color(black)("220 g/100 g H"_2"O")color(white)(a/a)|)))#

The answer is rounded to two sig figs, the number of sig figs you have for the mass of water that can dissolve #"11.1 g"# of silver nitrate.