# What is the solution set for #abs(2x – 3) – 10 = –1#?

##### 1 Answer

Aug 5, 2015

#### Explanation:

Start by isolating the modulus on one side of the equation

You are going to look at two cases for this equation

#(2x-3)>0# ,*which means that you have*

#|2x-3| = 2x-3#

and the equation is

#(2x-3)<0# ,*which will get you*

#|2x-3| = -(2x-3) = -2x+3#

and the equation is

Because you have no restriction for the values of