Question

What is the solution set for `x^2 + 2x + 10 = 0`?

Answer 1

`x =(-2+ sqrt( - 36))/ (2)`
`x =(-2- sqrt( - 36))/ (2)`

Explanation:

Since ------- `2^2` - `(4 xx1 xx 10)` < 0, x has imaginary roots

`x =(-b+- sqrt(b^2 - (4ac)))/ (2a)`
`x =(-2+- sqrt(2^2 - (4xx1xx10)))/ (2xx1)`
`x =(-2+- sqrt(4 - 40))/ (2)`
`x =(-2+ sqrt( - 36))/ (2)`
`x =(-2- sqrt( - 36))/ (2)`