# What is the solution set for x² + 4x - 3 = 9 + 5x?

$x = 4 \text{ or } x = - 3$
${x}^{2} + 4 x - 3 = 9 + 5 x$
${x}^{2} - x - 12 = 0$
$\left(x - 4\right) \left(x + 3\right) = 0$
$x = 4 \text{ or } x = - 3$