What is the specific heat of a substance that absorbs #2.5*10^3# joules of heat when a sample of #1 * 10^4# g of the substance increases in temperature from 10°C to 80°C?

1 Answer
Nov 6, 2015

Answer:

#s=3.57xx10^(-3)J/(g*""^@C)#

Explanation:

The amount of heat absorbed by the system could be calculated by:

#q=sxxmxxDeltaT#

where, #color(blue)(s)# is the specific heat capacity
#color(blue)(m)# is the mass of the object
#color(blue)(DeltaT)=T_f-T_i# is the change on temperature. #DeltaT=80 - 10 = 70^@C#

The specific heat capacity is then: #s=q/(mxxDeltaT)=(2.5xx10^3)/(1xx10^4xx70)=3.57xx10^(-3)J/(g*""^@C)#

Here is a video that fully explains this concept:
Thermochemistry | Enthalpy and Calorimetry.