# What is the spectator ion and net ionic equation of Zn(s)+Ag_2SO_4(aq)->ZnSO_4(aq)+2Ag(s)?

only sulfate $S {O}_{4}^{2 -}$ is a spectator ion
Zn is oxidised to $Z {n}^{2 +}$ in this reaction
sulfate remains as $S {O}_{4}^{2 -}$ throughout this reaction, so is chemically unchanged, so is a "spectator" in the transfer of electrons (otherwise known as chemistry!)
Zn begins the reaction as elemental Zinc ($Z {n}^{0}$) and ends the reaction as $Z {n}^{2 +}$ , so loses 2 electrons, so oxidation.
Ag begins the reaction as ionic Ag ($A {g}^{1 +}$) and ends the reactions as elemental Silver ($A {g}^{0}$), so gains 1 electron, so reduced.