What is the speed of an object that travels from #( -4,6,1) # to #( -1,4,-2 ) # over #2 s#?

1 Answer
Mar 20, 2018

Answer:

2,35 m/s

Explanation:

to calculate the speed you must know the distance that i suppose in straight line and in meters. You can calculate the distance with the Pigagora's theoreme in the space:
#d= sqrt (DeltaX^2+ Delta Y^2 +Deltaz^2)=sqrt(3^2+(-2)^2+ (-3)^2)=sqrt(22) = 4,7 m#
#v= (deltas)/(deltat) = (4,7 m)/(2s) = 2,35 m/s#