What is the speed of an object that travels from #( 8,-4,2) # to #( 7,-3,6 ) # over #3 s#?

1 Answer
Feb 29, 2016

Answer:

#v=sqrt 2 m/s#

Explanation:

#"Distance the point (8,-4,2) and (7,-3,6) may be calculated using:"#
#Delta x=sqrt((7-8)^2+(-3+4)^2+(6-2)^2)=sqrt(1+1+16)=sqrt 18 m#
#"The speed of an object is given by :"v=(Delta x)/t#
#v=sqrt 18/3#
#v=sqrt (9*2)/3#
#v=3*sqrt 2/3#
#v=sqrt 2 m/s#