What is the standard form of a polynomial #6x(x^2+2x+1)#?

1 Answer
Apr 3, 2016

Answer:

#6x^3+12x^2+6x#

Explanation:

#1#. Use the distributive property, #color(red)a(color(blue)b# #color(violet)(+c))=color(red)acolor(blue)b# #color(red)(+a)color(violet)c#, to multiply #6x# by each term within the brackets.

#color(red)(6x)(color(blue)(x^2)# #color(violet)(+2x)# #color(darkorange)(+1))#

#=color(red)(6x)(color(blue)(x^2))color(red)(+6x)(color(violet)(2x))color(red)(+6x)(color(orange)1)#

#2#. Simplify.

#=color(green)(|bar(ul(color(white)(a/a)6x^3+12x^2+6xcolor(white)(a/a)|)))#