# What is the standard form of a polynomial (7x^2 - 2x + 8) - (4x^2 + 9x - 1)?

Aug 13, 2016

$3 {x}^{2} - 11 x + 9$

#### Explanation:

The first step is to distribute the brackets.

$\Rightarrow 7 {x}^{2} - 2 x + 8 - 4 {x}^{2} - 9 x + 1$

now, collect $\textcolor{b l u e}{\text{like terms}}$

$\textcolor{b l u e}{7 {x}^{2} - 4 {x}^{2}} \textcolor{red}{- 2 x - 9 x} \textcolor{m a \ge n t a}{+ 8 + 1}$

$= 3 {x}^{2} - 11 x + 9 \text{ in standard form}$

Standard form means start with the term with the highest power of the variable, in this case ${x}^{2}$, followed by the next highest power and so on until the last term, the constant.