What is the standard form of a polynomial (9a^2-4-5a)-(12a-6a^2+3)?

Jul 5, 2017

See a solution process below:

Explanation:

First, remove all of the terms from parenthesis. Be careful to handle the signs of each individual term correctly:

$9 {a}^{2} - 4 - 5 a - 12 a + 6 {a}^{2} - 3$

Next, group like terms in descending order of the power of their exponents:

$9 {a}^{2} + 6 {a}^{2} - 5 a - 12 a - 4 - 3$

Now, combine like terms:

$\left(9 + 6\right) {a}^{2} + \left(- 5 - 12\right) a + \left(- 4 - 3\right)$

$15 {a}^{2} + \left(- 17\right) a + \left(- 7\right)$

$15 {a}^{2} - 17 a - 7$

Jul 5, 2017

$15 {a}^{2} - 17 a - 7$

Explanation:

$\left(9 {a}^{2} - 4 - 5 a\right) - \left(12 a - 6 {a}^{2} + 3\right)$

$\therefore = 9 {a}^{2} - 4 - 5 a - 12 a + 6 {a}^{2} - 3$

$\therefore = 15 {a}^{2} - 17 a - 7$