Question

What is the standard form of the equation of a circle with a center (-5, -7) and a radius of 3.8?

Answer 1

Standard form: `(x-h)^2+(y-k)^2=r^2`

with center `=(h,k)` and radius `=r`

Explanation:

For this problem, with center `=(-5,-7)` and radius `=3.8`

Standard form: `(x+5)^2+(y+7)^2=3.8^2=14.44`

hope that helped