What is the standard form of the equation of a circle with with the centre (-2,3) and radius 6?

1 Answer
Nov 23, 2015

Answer:

#(x+2)^2+(y-3)^2=36#

Explanation:

The equation for a circle is #(x-h)^2+(y-k)^2=r^2#, where #(h,k)# is the center of the circle and #r# is the radius.

This translates into: #(x+2)^2+(y-3)^2=36#

Common mistakes when writing the equation are not remembering to flip the signs of #h# and #k#. Notice that the center is #(-2,3)#, but the circle's equation has the terms #(x+2)# and #(y-3)#. Also, don't forget to square the radius.