# What is the standard form of the equation of a circle with x^2 + y^2 – 10x -4y + 13 =0?

Nov 29, 2015

The standard form is: ${\left(x - 5\right)}^{2} + {\left(y - 2\right)}^{2} = 16$

#### Explanation:

${x}^{2} + {y}^{2} - 10 x - 4 y + 13 = 0$

${x}^{2} - 10 x \textcolor{red}{+ 25} + {y}^{2} - 4 y \textcolor{red}{+ 4} + 13 \textcolor{red}{- 25} \textcolor{red}{- 4} = 0$

${\left(x - 5\right)}^{2} + {\left(y - 2\right)}^{2} - 16 = 0$

${\left(x - 5\right)}^{2} + {\left(y - 2\right)}^{2} = 16$