# What is the standard form of  y=(11x - x^2)(11 - x) ?

Feb 3, 2016

${x}^{3} - 22 {x}^{2} + 121 x$

#### Explanation:

The way we solve this equation is by using the distributive property. Here is an example of how it works:

In this case, we multiply $\left(11 x \cdot 11\right) + \left(11 x \cdot - x\right) + \left(- {x}^{2} \cdot - 11\right) + \left(- {x}^{2} \cdot - x\right)$.
This becomes $121 x + \left(- 11 {x}^{2}\right) + \left(- 11 {x}^{2}\right) + {x}^{3}$, which we can simplify to $121 x - 22 {x}^{2} + {x}^{3}$.

Standard form is $a {x}^{3} + b {x}^{2} + c x + d$, so lets try to rewrite our expression in this form.
It gos from highest degree to lowest, so let's right it like that. ${x}^{3} - 22 {x}^{2} + 121 x + 0$. We can ignore the zero, so we don't need to add it if we don't want to.

The final form is ${x}^{3} - 22 {x}^{2} + 121 x$